A polar covalent bond will form between which two atoms?
a. beryllium and fluorine (group 1 and group 7)
b. hydrogen and chlorine (group 7)
c. sodium and oxygen (group 1 and group 6)
d. fluorine and fluorine (group 7)

1 Answer

  • Types of Bonds can be predicted by calculating the difference in electronegativity.

    If, Electronegativity difference is,


                    Less than 0.4 then it is Non Polar Covalent


                    Between 0.4 and 1.7 then it is Polar Covalent 


                    Greater than 1.7 then it is Ionic


    For Be and F,

                        E.N of Fluorine          =   3.98

                        E.N of Beryllium        =   1.57


                        E.N Difference                2.41          (Ionic Bond)

    For H and Cl,

                        E.N of Chorine           =   3.16

                        E.N of Hydrogen        =   2.20


                        E.N Difference                0.96          (Polar Covalent Bond)

    For Na and O,

                        E.N of Oxygen          =   3.44

                        E.N of Sodium          =   0.93


                        E.N Difference                2.51          (Ionic Bond)

    For F and F,

                        E.N of Fluorine          =   3.98

                        E.N of Fluorine          =   3.98


                        E.N Difference                0.00         (Non-Polar Covalent Bond)


               A polar covalent bond is formed between Hydrogen and Chlorine atoms.