Claire’s mother is 4 years more than twice Claire’s age. The sum of their ages is 58 years.
Mathematics
velasquezfaith12
Question
Claire’s mother is 4 years more than twice Claire’s age. The sum of their ages is 58 years.
2 Answer

1. User Answers choixongdong
Let x = Claire's age
Claire’s mother is 4 years more than twice Claire’s age = 2x + 4
The sum of their ages is 58 years:
x + 2x + 4 = 58
3x + 4 = 58
3x = 54
x = 18
Claire's age = 18
Claire’s mother = 2(18)+4 = 36 + 4 = 40 
2. User Answers musiclover10045
claire's age = x
claire's mothers age = 2x+4 ( 4 more than twice claire's age)
sum is addition
x + 2x+4 = 58
add like terms ( x +2x = 3x)
3x +4 = 58
subtract 4 from each side:
3x = 54
divide both sides by 3
x = 54 /3
x = 18
Claire is 18 years old
Claire's mother is 2*18 = 36 +4 = 40 years old